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# please I need help on linear functions

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I am trying to solve this but I am stuck, I need help.

5x^2 - 3x + 3 = 0

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You have 3 different ways to solve this. This is a quadratic equation, so I will just post the easiest way to find the roots of the equation above

x=-b +- sqrt(b^2-4ac)/2a, where a=5, b =-3, c =3.  We have x= [-(-3) +- sqrt((-3)^2-4(5)(3))]/2(5) = [3 +- sqrt(9-60)]/10

x=[3+-sqrt(-51)]/10 = [3 +-i sqrt(51)]/10.

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